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To calculate the sum of 2000 integers, we change the program (that is, the while condition) in the editor and compile and run again.

If we need to calculate the sum of the first 5000 integers, we change the program again in the editor and compile and run it again.

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- We do this work again in a loop. Change the program in the editor, compile, run, change the program again, compile and run, and so on.
- Are we doing it in a loop? We can make our program more intelligent so that we don’t have to change the conditions every time.
- The upper limit is a variable of data type int. When the upper limit value is 1000, the program calculates the sum of the first 1000 integers.

When the upper limit value is 5000, the program calculates the sum of the first 5000 integers. If you want to download and read Cs606 Midterm Solved Papers Subjective then click the below link. A classic example is:

Suppose we need to calculate the area of a given circle.

Now we can reuse it and make it more efficient by asking the user to enter a value for the upper limit:

cout << “Please enter the upper limit for which you want to sum”; cin >> upper limit; We don’t have to change our program every time the limit changes. For the sum of integers, this program has become general. If you want to download Cs606 Midterm Solved Papers Subjective then click the below link.

We can calculate the sum of any number of integers without changing the program. To make the display command more understandable, we can change the cout command to:

- cout << “ The sum of the first “ << upper limit << “ integers is “ << sum; Sample program 2:

Problem Statement: Compute the sum of the even numbers for the given upper bound of the integers. - In this sense, they differ from human beings. If you want to download Cs606 Midterm Solved Papers Subjective then click the below link. For example, if someone asks you, “What time is it?”, “Time please?” or just “Time?” you still understand that it is asking for the time, but the computer is different.
- We analyze the problem and know that the while statement will be used. We only need to add even numbers. How can we decide whether a number is even or not? We know that number

We need to calculate the sum of the first 1000 integers by taking a sum variable of type int. It is good programming practice to initialize a variable before using it. Here we initialize the sum variable with zero.

Practically in our daily lives, we are constantly planning, organizing, and paying attention to fine details (if we want our plans to succeed). And it’s also fun to do these activities. If you want to download Cs606 Midterm Solved Papers Subjective then click the below link.

Suppose we don’t have a modulus operator in C. Is there any other way to find out even numbers? We know that in C integer division returns an integer and the decimal part is truncated.

So the expression (2 * (number / 2)) gives a number as the result if the number is even. So we can change our condition in the if statement as:

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